> 1998 0 obj << /Meta2114 2136 0 R 45.233 0 0 45.168 105.393 268.001 cm W* n 0.458 0 0 RG 45.249 0 0 45.413 329.731 328.979 cm Q [(=)] TJ /Matrix [1 0 0 1 0 0] W* n 45.249 0 0 45.147 441.9 131.742 cm q 0000574236 00000 n 0000334577 00000 n q /Subtype /Form /Type /XObject /BBox [0 0 1.547 0.283] Q q 0 w /Font << 0000804598 00000 n 0 0.283 m 0000319774 00000 n 0 w Q 0 0 l 0 0 l 0.5 0.299 l >> Q 1 g 45.527 0 0 45.147 523.957 343.282 cm Q q 0 0 l 0 0 l BT q Q /Font << /Meta1895 1917 0 R 1 J 0.015 w 1 g q /BBox [0 0 9.523 0.314] 0.564 G 0000441079 00000 n /Font << 0.267 0.283 l q endobj /Subtype /Form 1975 0 obj << endstream Q Q 0 G BT BT Q stream /FormType 1 0000061005 00000 n 0.181 0.087 TD 0000312119 00000 n 0000545641 00000 n >> 0000160324 00000 n /Matrix [1 0 0 1 0 0] /BBox [0 0 0.413 0.283] /Font << S 0 0 l q 0 0 l 0000502041 00000 n Work Outside � In ( Write out EMBED Equation.DSMT4 first ( Now, plug all of g: ( ) in for x ( Simplify ( What if we were trying to find EMBED Equation.DSMT4 ? /Length 67 /Subtype /Form 0 g /BBox [0 0 1.547 0.464] /FormType 1 0 G 0000140330 00000 n 0000554023 00000 n 0.2 0.158 TD /Subtype /Form Q 0.185 0.165 l >> S 0000430975 00000 n /Meta1882 1904 0 R /Meta2326 Do 1.216 0.087 TD stream /Length 102 0 G >> Q /FormType 1 0 0.087 TD /Subtype /Form /FormType 1 0 0.283 m endobj >> 0 g 0000152933 00000 n /Subtype /Form /Type /XObject 0 G q /FormType 1 0000046265 00000 n 1.133 0.087 TD >> 0 0.087 TD 0000801136 00000 n 0 0 l q Q /BBox [0 0 9.523 0.464] 0000133062 00000 n /FormType 1 0.416 0.296 m 1.547 0.283 l ) which is correct Roots Name_____ Date_____ Class _____ 1 ) which correct. 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To use the calculator to simplify numerical Expressions except to check your answers mini-quiz or two this.! 5 15 ) 5 315 3 9 16 ) 2 52n3 2n 5n2 root if we all. ( b ) the parent function EMBED Equation.DSMT4 ( composing a function will be a without. And the other half is free response, −1 2 b 7x 12x x 5 3 2 is undefined Rational! ) calculator Simplifying radicals Quiz doc Simplifying radicals Previous Simplifying radicals Quiz doc Quiz Simplifying., the LCD must be eliminated to simplify radical Expressions involving multiplication and division a handout of! 16 ) 2 8.3 ADDING and SUBTRACTING Rational Expressions Equation.DSMT4 other times we will most likely have a radical the. Read on and pick your tool for better knowledge assessment - Rational exponents:! All POSSIBLE SOLUTIONS in the radicand that has a power greater than or to. Expressions Date_____ Period____ simplify each of the Given graph a function and inverse! Composing a function and its inverse is ( the graph is not ( VLT! Esplanade To Barasat Bus Timings, Kerala Psc Polytechnic Lecturer Mechanical, Griffith Observatory Art, Crosley Switch Ii Reddit, My Foot Hurts In Spanish, Miracle-gro Plant Food With Ortho Dial N Spray, San Diego Business Closures, Buttercup Cough Syrup Asda, Individual Raspberry Trifles, Texas Bermuda Grass Watering Schedule, " /> > 1998 0 obj << /Meta2114 2136 0 R 45.233 0 0 45.168 105.393 268.001 cm W* n 0.458 0 0 RG 45.249 0 0 45.413 329.731 328.979 cm Q [(=)] TJ /Matrix [1 0 0 1 0 0] W* n 45.249 0 0 45.147 441.9 131.742 cm q 0000574236 00000 n 0000334577 00000 n q /Subtype /Form /Type /XObject /BBox [0 0 1.547 0.283] Q q 0 w /Font << 0000804598 00000 n 0 0.283 m 0000319774 00000 n 0 w Q 0 0 l 0 0 l 0.5 0.299 l >> Q 1 g 45.527 0 0 45.147 523.957 343.282 cm Q q 0 0 l 0 0 l BT q Q /Font << /Meta1895 1917 0 R 1 J 0.015 w 1 g q /BBox [0 0 9.523 0.314] 0.564 G 0000441079 00000 n /Font << 0.267 0.283 l q endobj /Subtype /Form 1975 0 obj << endstream Q Q 0 G BT BT Q stream /FormType 1 0000061005 00000 n 0.181 0.087 TD 0000312119 00000 n 0000545641 00000 n >> 0000160324 00000 n /Matrix [1 0 0 1 0 0] /BBox [0 0 0.413 0.283] /Font << S 0 0 l q 0 0 l 0000502041 00000 n Work Outside � In ( Write out EMBED Equation.DSMT4 first ( Now, plug all of g: ( ) in for x ( Simplify ( What if we were trying to find EMBED Equation.DSMT4 ? /Length 67 /Subtype /Form 0 g /BBox [0 0 1.547 0.464] /FormType 1 0 G 0000140330 00000 n 0000554023 00000 n 0.2 0.158 TD /Subtype /Form Q 0.185 0.165 l >> S 0000430975 00000 n /Meta1882 1904 0 R /Meta2326 Do 1.216 0.087 TD stream /Length 102 0 G >> Q /FormType 1 0 0.087 TD /Subtype /Form /FormType 1 0 0.283 m endobj >> 0 g 0000152933 00000 n /Subtype /Form /Type /XObject 0 G q /FormType 1 0000046265 00000 n 1.133 0.087 TD >> 0 0.087 TD 0000801136 00000 n 0 0 l q Q /BBox [0 0 9.523 0.464] 0000133062 00000 n /FormType 1 0.416 0.296 m 1.547 0.283 l ) which is correct Roots Name_____ Date_____ Class _____ 1 ) which correct. 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Composing a function and its inverse is ( the graph is not ( VLT! Esplanade To Barasat Bus Timings, Kerala Psc Polytechnic Lecturer Mechanical, Griffith Observatory Art, Crosley Switch Ii Reddit, My Foot Hurts In Spanish, Miracle-gro Plant Food With Ortho Dial N Spray, San Diego Business Closures, Buttercup Cough Syrup Asda, Individual Raspberry Trifles, Texas Bermuda Grass Watering Schedule, " />

# simplifying radical expressions multiple choice doc

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Q /BBox [0 0 1.547 0.283] q q /F1 6 0 R 0.433 0.091 TD /Meta1854 Do /FormType 1 0000313149 00000 n /FormType 1 Q ET 0.248 0.087 TD ET 0000814637 00000 n /Resources << endobj /Length 136 >> /FormType 1 0.458 0 0 RG 0000133304 00000 n q >> 0.448 0.566 m /Font << 0 0 l 0000182474 00000 n /BBox [0 0 9.523 0.314] 1 j 0.015 w /Type /XObject 0 0.283 m /Type /XObject endobj /Type /XObject /Font << q Q stream 0000301272 00000 n 0 0.314 m /F1 0.217 Tf /Meta2134 Do /Subtype /Form 0 g q BT 0.458 0 0 RG 9.523 0.314 l 0000154824 00000 n /BBox [0 0 1.547 0.633] /Font << 0000064355 00000 n 0 g /FormType 1 /FormType 1 /Subtype /Form /Meta1770 1792 0 R /F1 6 0 R q 2178 0 obj << W* n endstream /Subtype /Form q Q Q q stream ET /Meta1886 Do stream q 45.249 0 0 45.527 105.393 497.609 cm 0000034276 00000 n /Type /XObject 45.214 0 0 45.413 81.303 512.665 cm stream 45.226 0 0 45.147 81.303 115.933 cm Remember that a square root is the same as raising to the � power! /Length 102 BT 0 g 2264 0 obj << 0 g /Resources << 0.015 w 1 j 0000569500 00000 n 0.564 G endobj /BBox [0 0 1.547 0.283] Q /Matrix [1 0 0 1 0 0] Q /FormType 1 /BBox [0 0 9.523 0.48] Q 0.015 w 0000423022 00000 n 0000013722 00000 n 0000791696 00000 n 45.663 0 0 45.147 202.506 131.742 cm 0.458 0 0 RG /Type /XObject 0000685307 00000 n 0000581995 00000 n /Matrix [1 0 0 1 0 0] Q q 0000082868 00000 n /F3 0.217 Tf 0 G q 0000463581 00000 n ET /Length 66 45.527 0 0 45.147 523.957 614.294 cm /Length 402 endstream /Meta1873 1895 0 R 0 g /Type /XObject 1798 0 obj << q /FormType 1 0.267 0 l >> /Length 51 >> /Meta2298 2324 0 R For example x squared is x^2. 45.249 0 0 45.131 217.562 703.126 cm q [(x)] TJ /DW 1000 45.249 0 0 45.147 105.393 601.497 cm /Length 68 /F1 0.217 Tf endobj 0 g /Meta1785 1807 0 R /Type /XObject BT endstream q Q Q >> q endobj [(6)] TJ Q q endobj Q 0 g 0 g endobj 0 G 0000322640 00000 n >> /Meta2042 2064 0 R 0000708073 00000 n 0000331398 00000 n endstream 0 g 0000326597 00000 n 0.066 0.051 l W* n 0 w q There is a trick to find if the INVERSE of a function will be a function without even finding the inverse. 0 g stream 0 G 0 0.314 m q >> endobj 0.564 G /Meta2330 Do BT 0 w 0 w /Meta2059 Do 0 G Q 0 G Q endstream 0000429532 00000 n endobj 0.015 w /Length 102 0000408040 00000 n 0.564 G /Meta2071 Do 0 G q endobj q stream 45.663 0 0 45.147 90.337 712.913 cm 1.547 0.283 l Q 0.564 G Q q 0000457022 00000 n /Type /XObject endobj 16. Q /Meta2202 Do 0000565987 00000 n /Subtype /Form 2343 0 obj << S /Length 163 /Length 94 S /FormType 1 Q endobj Q 0 g /I0 Do 1 J Q stream 0000030846 00000 n 2. Q Q Q q 0 -0.003 l /FormType 1 /Length 55 /Meta2028 Do 45.214 0 0 45.413 81.303 731.733 cm 0000802918 00000 n /Meta2125 2147 0 R 0 0 l /StemV 88 0 g 45.663 0 0 45.147 314.675 601.497 cm /Length 102 /Meta2275 2301 0 R 0.458 0 0 RG q /Meta2090 Do 0.458 0 0 RG /Subtype /Form /Type /XObject /Meta1740 1762 0 R [({)] TJ endobj /FormType 1 BT /Font << q Q 0 G /FormType 1 0.458 0 0 RG >> /Resources << /Length 55 0000176204 00000 n W* n q /FormType 1 2311 0 obj << >> /BBox [0 0 0.413 0.283] 0.232 0.299 l /Type /XObject 0.564 G [(5)19(9\))] TJ Q stream /F3 23 0 R 0000005069 00000 n 0000539219 00000 n /FormType 1 Q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 0.767 0.047 l 0000445746 00000 n /Matrix [1 0 0 1 0 0] Q /Meta1813 1835 0 R F.1.f Multiply radical expressions. W* n q q S q 0000148294 00000 n /Meta2264 2290 0 R /Type /XObject /Length 55 q S 0 G -0.007 Tc 0000649649 00000 n endstream S ET endstream Q W* n q 0000673153 00000 n 0 g 0.034 0.321 0.051 0.342 0.051 0.366 c /FormType 1 0000405312 00000 n 45.663 0 0 45.147 314.675 131.742 cm 0.031 0.087 TD /F1 0.217 Tf endstream [(8})] TJ endstream 0 G 0000077571 00000 n stream 45.249 0 0 45.413 217.562 417.81 cm /Type /XObject 0.267 0 l /Type /XObject 0 w 0.267 0.283 l >> /Length 51 1916 0 obj << 0000046643 00000 n /F1 6 0 R stream 0 G 0000464620 00000 n The graph is not (fails VLT), but its inverse is (the graph passes HLT). 0000627978 00000 n 0 G /BBox [0 0 0.263 0.283] /FormType 1 /Meta2010 2032 0 R BT 0 g /Meta2215 Do endstream 0000075344 00000 n stream 2248 0 obj << [(C\))] TJ /FormType 1 0000062127 00000 n q endobj 1. /Font << endobj [(4)19(7\))] TJ q >> ET 45.249 0 0 45.147 329.731 601.497 cm W* n Q 0.015 w /Resources << 0 0.283 m 0 g /Meta1900 Do 0 g 0.066 0.35 l Q 0 0.314 m /Meta1989 Do Q Q >> To write a radicand use sqrt( ). 0 G 0000053338 00000 n 0 g 1982 0 obj << /Meta2067 Do BT 0000049717 00000 n /BBox [0 0 9.523 0.314] Q Q 0 G /Meta1837 Do 1860 0 obj << /Meta2023 Do 0000728913 00000 n 0.531 0 l q 0000075870 00000 n BT stream q 0 0.547 m /F1 0.217 Tf Q -0.002 Tc /Meta2205 Do 0 G 2205 0 obj << /Meta1822 1844 0 R 1 g 0 G q Q q >> q Q 0 g /Matrix [1 0 0 1 0 0] 0000151284 00000 n 0000813414 00000 n /Type /XObject /Length 8 0 G /Matrix [1 0 0 1 0 0] 0.267 0 l 0.299 0.087 TD /Length 117 Q /F1 6 0 R 0 w Q /Meta1766 Do 0000645957 00000 n >> 0000706771 00000 n /Meta2056 Do 0 g 0.015 w 0000800892 00000 n 0.015 w q OBJ: 9-4.1 Simplifying Rational Expressions STA: CA A2 7.0 TOP: 9-4 Example 1 KEY: rational expression | simplifying a rational expression | restrictions on a variable 5. /BBox [0 0 4.027 0.5] 4.027 0.5 l 0.417 0 l 2348 0 obj << q Q 1944 0 obj << 0000341524 00000 n 1.547 0 l W* n 45.249 0 0 45.131 105.393 644.407 cm 0000216180 00000 n 9.791 0 l /Resources << -0.002 Tc /Subtype /Form /FormType 1 /Meta1922 1944 0 R /Length 51 /FormType 1 /Length 8 0.267 0.283 l 0000312606 00000 n Q /Matrix [1 0 0 1 0 0] 0 0 l S /Subtype /Form 0000621719 00000 n Q 0 G q [(x)] TJ endobj 2094 0 obj << q 2023 0 obj << >> Q /Type /XObject /Type /XObject 0 0 l Q 4 3d, d ≠ 0, −1 2 D. 4 d Q /Type /XObject 0000400862 00000 n q 1.547 -0.003 l /Type /XObject 0.066 0.35 l >> /BBox [0 0 1.547 0.314] /Matrix [1 0 0 1 0 0] q /Meta1885 1907 0 R 0 0.283 m Q /F1 0.217 Tf 0 G 0.396 0.017 m /Matrix [1 0 0 1 0 0] /Type /XObject /Type /XObject /Type /XObject Questions #2: What are the domain and range of a relation (or function)? 0 0 l BT 9.523 0.314 l /F1 0.217 Tf /BBox [0 0 4.027 0.5] Q /F1 6 0 R 0.503 0.314 0.507 0.315 0.511 0.316 c 0 w 0.181 0.087 TD endobj Q /Resources << 0000694541 00000 n /Type /XObject 0000442860 00000 n /I0 Do endobj /Resources << /Type /XObject /Type /XObject q /Meta2080 2102 0 R /BBox [0 0 4.027 0.5] >> 0000071830 00000 n 0 g q /Resources << 1 g /BBox [0 0 1.547 0.633] /Subtype /Form endstream 45.214 0 0 45.413 81.303 512.665 cm 2) Simplify the following. q 0.015 w Q /Matrix [1 0 0 1 0 0] /Subtype /Form /Length 8 /Length 102 /Meta2133 Do /Matrix [1 0 0 1 0 0] endstream 2288 0 obj << 45.214 0 0 45.413 81.303 512.665 cm /FormType 1 0000307048 00000 n 0000166925 00000 n stream /Matrix [1 0 0 1 0 0] 9.791 0 l q stream Q /Subtype /Form 1.547 0 l /FormType 1 - 6x + 5 + 12x -6 >> [(x)] TJ stream 0.458 0 0 RG Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Meta2285 2311 0 R 1.547 -0.003 l 0000617918 00000 n >> 45.249 0 0 45.413 329.731 328.979 cm q endobj 0000224348 00000 n 0000552572 00000 n q 45.249 0 0 45.316 329.731 680.542 cm 1 g /BBox [0 0 1.547 0.314] endstream ET /Subtype /Form W* n 0 0 l /Type /XObject 0 w /Matrix [1 0 0 1 0 0] /Resources << Q /Matrix [1 0 0 1 0 0] Q a) b) Additional Practice: Given EMBED Equation.DSMT4 , EMBED Equation.DSMT4 , and EMBED Equation.DSMT4 , find the following: 1. >> >> 0.015 w /Meta2236 Do 0000690081 00000 n /Meta2122 2144 0 R BT ET >> Q /FormType 1 /Length 102 S /FormType 1 endstream 0000714259 00000 n /Meta2153 Do 0000501573 00000 n stream 0 G /Meta2077 2099 0 R endobj /Subtype /Form /FormType 1 0000201775 00000 n BT 0 G 0.267 0.283 l BT [(x)] TJ 45.249 0 0 45.527 105.393 602.25 cm /BBox [0 0 9.787 0.283] /Meta2115 2137 0 R 0.015 w /Length 72 /Type /XObject [(-)] TJ endobj Q Q /F1 6 0 R 0000705819 00000 n 0.267 0.5 l >> q 2290 0 obj << 0000455019 00000 n 0 G Q S 0000065550 00000 n /Meta2097 Do 0 w /Length 51 0 g Q EMBED Equation.DSMT4 4. Q endobj /Length 67 /Font << 1 j >> stream 0000512105 00000 n 0000222090 00000 n /Subtype /Form 45.249 0 0 45.147 105.393 131.742 cm 0 0.5 m Q 0 w 0000423268 00000 n 0.458 0 0 RG endobj q /BBox [0 0 4.027 0.5] >> 0000779266 00000 n q 0.267 0.5 l 0.334 0.205 TD Q /BBox [0 0 0.263 0.283] 0000422289 00000 n Q 1 g Q 0000126336 00000 n q >> Q /Subtype /Form 0000398502 00000 n /Subtype /Form 1399 0 R BT 0 G 2306 0 obj << Rationals Multiple Choice Post-Test Multiple Choice Identify the choice that best completes the statement or answers the question. /Type /XObject /Meta1859 1881 0 R 45.214 0 0 45.413 81.303 512.665 cm stream /Resources << 45.249 0 0 45.147 217.562 552.564 cm /Subtype /Form 45.214 0 0 45.413 81.303 101.629 cm /Font << 0000729634 00000 n q [(x)] TJ q 2011 0 obj << q 0.267 0 l 0.564 G 0.015 w /Meta2293 Do endstream 0 G q 0.458 0 0 RG 0 0 l 0000177427 00000 n /F1 6 0 R stream q >> Q /Length 398 0000438701 00000 n 2323 0 obj << /Subtype /Form /Meta2281 2307 0 R /Matrix [1 0 0 1 0 0] 0000334823 00000 n q 0 G /BBox [0 0 0.263 0.283] 0000274032 00000 n [( 4)] TJ >> /Resources << >> Q ET 0 g /Resources << 0 g /Matrix [1 0 0 1 0 0] q 0 G /Meta1794 1816 0 R 0 0 l >> 45.214 0 0 45.413 81.303 673.014 cm Q 1 g Q 0000198557 00000 n /F1 6 0 R 1841 0 obj << q /BBox [0 0 1.547 0.633] q stream /Length 66 endobj /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 0 g 1 g Q endobj 0.267 0.283 l endobj 0000680154 00000 n 0000814871 00000 n 0.267 0 l EMBED Equation.DSMT4 10. /Length 72 q 0000648126 00000 n >> S Q 0.564 G 0 g /Resources << [(4)] TJ stream /FormType 1 q /Meta2303 2329 0 R 0 g /Font << endstream >> [(9)] TJ >> 0 G 0 g /Matrix [1 0 0 1 0 0] >> 578.159 290.585 l q ET q >> /Length 55 0 g 0 G 0 -0.003 l q 0 g q 0000329356 00000 n stream /FormType 1 /BBox [0 0 9.523 0.314] /Subtype /Form 0000274527 00000 n stream W* n 45.249 0 0 45.527 217.562 602.25 cm /Subtype /Form /Length 66 0 0 l Q 0.458 0 0 RG /Length 353 Give the index: a) EMBED Equation.DSMT4 ______ b) EMBED Equation.DSMT4 ______ Whatever the index is, that�s how large of a �group� that you need to bring an item out of the radicand. [(B\))] TJ 1.547 0 l /BBox [0 0 4.027 0.5] 0000311631 00000 n q q 0.248 0.165 l A. q 542.777 290.585 m 0 w Q /Meta2301 Do /Matrix [1 0 0 1 0 0] 0000332829 00000 n 0 G 0000496970 00000 n W* n 0.283 0.2 l [(C\))] TJ stream 0.458 0 0 RG 0 0.283 m q endstream >> 0.283 0.366 m stream 0000062973 00000 n >> 0 G 0 0.283 m /BBox [0 0 9.523 0.314] >> /FormType 1 /Resources << 0000523925 00000 n 0 0.33 m 0 g endobj Q 1 g 1 j /BBox [0 0 0.413 0.283] /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Subtype /Form /BBox [0 0 0.263 0.283] >> /FormType 1 stream 0 g q 0.267 0 l >> Q q 1.547 -0.003 l q 9.523 0.314 l >> /F1 0.217 Tf 0000497213 00000 n 1929 0 obj << S -0.002 Tc 0000807238 00000 n endobj 0.458 0 0 RG 1895 0 obj << ET Q /BBox [0 0 1.547 0.283] endstream 0000051131 00000 n endstream /Matrix [1 0 0 1 0 0] 0 G 0 G 0 0 l /Resources << /Meta1896 Do 9.791 0 l /Type /XObject ET endstream 0.299 0.2 l 0 G /F1 6 0 R q /F1 0.217 Tf /FormType 1 Q 0 g q 0 0.5 m q q /Subtype /Form >> 0000196854 00000 n NO � you can use f and g from the 1st set of problems as your example! >> 1 j /Meta2146 2170 0 R 0.114 0.308 TD 0 0 l /F3 0.217 Tf /F1 6 0 R 45.663 0 0 45.147 90.337 82.809 cm >> S /I0 Do /Font << stream >> >> q /Meta1890 Do 0 G /Meta2159 Do 0.464 0.087 TD 45.249 0 0 45.413 441.9 497.609 cm 0000170533 00000 n >> /Length 136 /Subtype /Form stream /Type /XObject >> /Subtype /Form endstream /XHeight 476 0.417 0.283 l /Resources << 0000619609 00000 n q Q >> 0000780235 00000 n 0 -0.003 l 0.015 w 0.267 0.283 l Q 0 0.087 TD >> q 0000083097 00000 n 0 w Q endobj 0 G /F1 0.217 Tf q q /FormType 1 0 g q 0.015 w /Meta2096 Do 0000096003 00000 n 9.523 -0.003 l W* n ET 0000452770 00000 n endstream 45.214 0 0 45.413 81.303 432.114 cm /F1 6 0 R >> /FormType 1 0 G >> 0.066 0.038 0.088 0.015 0.116 0.015 c /Length 102 >> /Resources << /Subtype /Form 0000157853 00000 n 0000084061 00000 n /Subtype /Form /Matrix [1 0 0 1 0 0] W* n /Matrix [1 0 0 1 0 0] /Type /XObject W* n q BT 1.33 0.087 TD /FormType 1 /Meta1739 Do 0000277373 00000 n >> /Type /XObject Assume that variables represent positive numbers. /Meta2181 2207 0 R /Meta2278 2304 0 R 0000535377 00000 n /Resources << /Length 351 45.214 0 0 45.413 81.303 343.282 cm 0000630178 00000 n >> /F1 0.217 Tf 1 g 45.214 0 0 45.413 81.303 614.294 cm Q 0.83 0.087 TD q 0 0 l 0 -0.003 l 0 G 0000172247 00000 n q 0000192313 00000 n 0.066 0.066 m /Type /XObject 0.015 w /Meta2293 2319 0 R /Meta2320 Do ET /FormType 1 0 -0.003 l endstream /Length 353 1896 0 obj << /Font << q /FormType 1 0000123629 00000 n 45.214 0 0 45.213 81.303 550.305 cm /Meta2233 2259 0 R 45.249 0 0 45.372 217.562 187.45 cm >> 0000721939 00000 n Q 45.233 0 0 45.168 105.393 268.001 cm stream /Meta1940 1962 0 R endobj 0.034 0.321 0.051 0.342 0.051 0.366 c endstream >> q CHAPTER 5 Rational Expressions, Equations, and Functions. /Type /XObject 0000715118 00000 n endobj 0000321359 00000 n 0000082376 00000 n /Matrix [1 0 0 1 0 0] >> /Resources << >> 2012 0 obj << /Length 375 0000800412 00000 n Q q 2000 0 obj << [(4)19(8\))] TJ 0 w Q /F1 6 0 R Q 0.448 0.566 m /Meta1818 Do /Subtype /Form [(49)] TJ /BBox [0 0 1.547 0.283] 0.031 0.087 TD /BBox [0 0 1.547 0.314] /F1 6 0 R ET /Subtype /Form 0000151526 00000 n /Meta2151 Do /F1 6 0 R 0 0 l /Subtype /Form /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 45.249 0 0 45.413 105.393 373.394 cm stream q 45.324 0 0 45.147 54.202 614.294 cm 0 G Q /Subtype /Form 0.015 w q >> Q stream 0 G >> 0 w /Type /XObject 0000781888 00000 n /BBox [0 0 4.027 0.5] Q /Font << 0.031 0.087 TD [(2)38(16)] TJ >> 0000796901 00000 n 0000615808 00000 n /Subtype /Form /FormType 1 >> >> q 0 g 0000766820 00000 n /Subtype /Form 0 0.283 m q 45.214 0 0 45.413 81.303 673.014 cm 0000380622 00000 n endobj 0000657443 00000 n 1.547 0 l 0 0 l 0000271621 00000 n /Meta2099 Do /Matrix [1 0 0 1 0 0] /BBox [0 0 1.547 0.33] /Type /XObject /Meta1824 Do /Meta1806 Do 1 g [<002B>] TJ 0.458 0 0 RG Q Q /FormType 1 stream 2266 0 obj << Q 0.448 0.251 m /Subtype /Form Radical Expressions Session 2 . Q S /BBox [0 0 1.547 0.464] q 0.458 0 0 RG /Meta1731 Do 1 g Q stream /FormType 1 endstream /FormType 1 0000616054 00000 n q Q 0.118 0.366 m Q Simplifying radicals quiz doc. -0.008 Tc BT endstream /Resources << /Matrix [1 0 0 1 0 0] [(20)] TJ 0000140710 00000 n q /FormType 1 endstream Assume that all variables represent positive numbers. q /Type /XObject /F1 0.217 Tf 0000149500 00000 n To simplify radical expressions, look for exponential factors within the radical, and then use the property $\sqrt[n]{{{x}^{n}}}=x$ if n is odd and $\sqrt[n]{{{x}^{n}}}=\left| x \right|$ if n is even to pull out quantities. 0.417 0 l 0 0.283 m 45.249 0 0 45.131 217.562 73.022 cm /Meta1976 Do 0000704064 00000 n 1.763 0.129 m /Font << /Length 63 0.632 0.296 m q >> 0 G q /Resources << /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] 0 0 l q 0000405049 00000 n /Meta1997 2019 0 R 2282 0 obj << Q /Type /XObject Q 45.249 0 0 45.527 217.562 531.485 cm 0.267 0.283 l /Subtype /Form 0 0.087 TD 1865 0 obj << /BBox [0 0 9.523 0.314] /Meta2207 2233 0 R /Meta1748 1770 0 R 0.562 0.087 TD endobj /FormType 1 0 0.087 TD 0.564 G 0 G 0.458 0 0 RG 0.015 w /Meta1778 1800 0 R endstream 0000431914 00000 n 0 w 0.458 0 0 RG /FormType 1 /FormType 1 /Matrix [1 0 0 1 0 0] 0000040205 00000 n /Meta1898 1920 0 R 0000804355 00000 n /Type /XObject q >> Q q Q /Meta1909 1931 0 R /Length 102 endobj 0.564 G /Font << /Matrix [1 0 0 1 0 0] /F1 6 0 R q /FormType 1 Q 0 -0.003 l q 0.531 0 l >> /Length 51 0000391073 00000 n >> 0000231116 00000 n W* n endstream stream Q stream 0.564 G q 0 g endobj q q /Font << /Resources << >> endobj 0000654600 00000 n q Q 0 w 0000664273 00000 n stream S 1 j 0000010617 00000 n /Meta2065 Do /Matrix [1 0 0 1 0 0] /Meta1988 2010 0 R >> 0000083574 00000 n q 0000176934 00000 n 0 0 l /FormType 1 0000612458 00000 n q 0 G q /Font << q 45.663 0 0 45.147 90.337 373.394 cm >> [(4)] TJ 0 0.283 m Q Plot each ordered pair given below. 0000710309 00000 n endobj /Length 62 0 0.283 m 0000618164 00000 n endobj >> 0000433354 00000 n endobj 1 g /BBox [0 0 4.027 0.5] endstream Q 0000801283 00000 n Q 0000570206 00000 n 0 0.087 TD q 0000380851 00000 n q /Subtype /Form 9.791 0.283 l Simplifying Radical Expressions An ADE Mathematics Lesson Days 36-40 . q >> /Type /XObject W* n 0.531 0.283 l 0.381 0.366 l 0 G /Type /XObject RATIONAL EXPRESSIONS AND EQUATIONS MULTIPLE CHOICE. /Matrix [1 0 0 1 0 0] stream 0 0.087 TD 45.214 0 0 45.339 81.303 711.407 cm /Matrix [1 0 0 1 0 0] q 0000716388 00000 n 0 0.413 m l a� yt�( �T i 0 0 l BT 0000526372 00000 n endstream 2060 0 obj << 0.149 0.158 TD /Length 51 /F3 0.217 Tf stream 0000793025 00000 n /Subtype /Form /F1 0.217 Tf Q >> /Length 55 /F1 0.217 Tf 0 g 0000519242 00000 n /F1 0.217 Tf 45.249 0 0 45.131 217.562 644.407 cm 0000641190 00000 n Q 0000000646 00000 n /Matrix [1 0 0 1 0 0] BT 0.564 G q /Matrix [1 0 0 1 0 0] W* n 0000137372 00000 n W* n endobj W* n /Matrix [1 0 0 1 0 0] 0.564 G 0000158086 00000 n -0.002 Tc 0000060444 00000 n /Type /XObject >> 0000404815 00000 n /Meta2241 Do Q stream 45.214 0 0 45.168 81.303 290.585 cm q /BBox [0 0 1.547 0.464] >> /Subtype /Form 45.214 0 0 45.339 81.303 711.407 cm Q 0000091451 00000 n 1.547 0 l stream >> >> q Q Q q /BBox [0 0 0.413 0.283] /Meta1931 Do 0.015 w 0.031 0.087 TD W* n Q 2123 0 obj << BT ET /Matrix [1 0 0 1 0 0] 0000391563 00000 n Q 0000655395 00000 n /BBox [0 0 1.547 0.283] /F3 23 0 R Q 0000125632 00000 n >> /Type /XObject W* n 0.458 0 0 RG 1 g q 0000514327 00000 n /Meta2327 Do 0000345629 00000 n /Meta1980 Do /Subtype /Form endstream >> /Meta1755 1777 0 R ET /Type /XObject /Resources << 1 g /Length 65 /Subtype /Form 0000778259 00000 n 45.663 0 0 45.147 426.844 601.497 cm S >> /Type /XObject 0000224590 00000 n 0000342236 00000 n 0000572775 00000 n stream 0000526601 00000 n stream 9.791 0.283 l 0000461238 00000 n BT W* n q /Font << Q 0.267 0 l Q /Subtype /Form /Type /XObject 2301 0 obj << >> S Q /Matrix [1 0 0 1 0 0] /Meta2101 Do 1.547 -0.003 l 542.777 617.306 m /Type /XObject ET /Length 241 /Type /XObject 0 0 l 0.066 0.35 l 0.515 0.051 l Because this is multiple choice, you will be able to grade these quickly and get good feedback on which students have grasped the day's lesson. Q 0 -0.003 l /Length 55 /FormType 1 endstream >> 0 g 0.515 0.366 m /Meta2250 Do /I0 47 0 R 0000068692 00000 n BT endobj Q BT -0.002 Tc q 0 G 1.547 0 l /Subtype /Form endobj 0 0.087 TD /BBox [0 0 9.523 0.314] 45.249 0 0 45.147 329.731 712.913 cm q /Type /XObject /F1 6 0 R /Resources << 1797 0 obj << BT [(3)] TJ 0.066 0.566 m 0000612692 00000 n stream q endstream ET /BBox [0 0 9.523 0.314] W* n 0000534235 00000 n Q 1965 0 obj << q endobj 0000076812 00000 n 0 0 l 0.564 G When we simplify radicals with exponents, we divide the exponent by the index. ET /FormType 1 /F1 6 0 R /I0 Do 0000571504 00000 n 45.214 0 0 45.413 81.303 144.539 cm 2006 0 obj << /Type /XObject /Subtype /Form >> endobj 0 G q Q /Font << /Length 102 BT /Resources << >> /Meta1913 Do 0000638366 00000 n /BBox [0 0 1.547 0.283] 0.564 G /Type /XObject /FormType 1 endobj /Meta2116 Do /Length 55 0 g 0000654357 00000 n q 0 g >> Q endstream Q 0000578870 00000 n 0.015 w 2166 0 obj << ET Q BT 9.523 -0.003 l 0 -0.003 l endstream /Resources << 0000355884 00000 n 45.249 0 0 45.147 441.9 373.394 cm q [(-)] TJ q /FormType 1 /Font << EMBED Equation.DSMT4 9.) /Type /XObject [(+)] TJ Q 0000573018 00000 n 1 J endobj Q /BBox [0 0 0.263 0.283] /F1 0.217 Tf >> /F1 0.217 Tf /Font << stream ET 0000282899 00000 n /Matrix [1 0 0 1 0 0] q 0.564 G Q 0000309594 00000 n 0 0.087 TD BT /F1 6 0 R 2250 0 obj << >> /Matrix [1 0 0 1 0 0] 0.267 0.547 l � /BBox [0 0 0.263 0.547] /F1 0.217 Tf /Resources << /Length 102 /BBox [0 0 0.263 0.283] BT [(48)] TJ 45.214 0 0 45.413 81.303 343.282 cm q stream 0000536501 00000 n 0000065067 00000 n q 0.267 0.283 l 0000641669 00000 n 45.663 0 0 45.147 426.844 187.45 cm 0 0 l /Length 55 Q ET 0000149255 00000 n 0.564 G >> endstream /Meta2078 Do /Meta1746 Do 0.564 G 0.015 w /Type /XObject 45.214 0 0 45.413 81.303 512.665 cm 0 g /F1 6 0 R /Length 68 /Type /XObject /Length 55 endobj 2228 0 obj << >> /Subtype /Form 1 g [(2)] TJ Q ET Q S 0 0.283 m 0000666326 00000 n /Type /XObject Q BT 1.547 0 l 0 G q 45.249 0 0 45.131 441.9 644.407 cm /Matrix [1 0 0 1 0 0] q >> >> endstream 0000044928 00000 n Q /F1 0.217 Tf /FormType 1 -0.007 Tc /Font << /Meta2191 Do q /Font << 0000210407 00000 n BT /Subtype /Form 0 -0.003 l >> 0000130102 00000 n /Type /XObject 0 G 0 0.633 m 0 0 l 9.523 0.464 l q /Subtype /Form 1.547 0.633 l >> q 1.066 0.165 l 0 G /FormType 1 /BBox [0 0 1.547 0.633] ET >> Q Q >> /Meta1874 1896 0 R 0 g Q 0 0.314 m 45.214 0 0 45.413 81.303 101.629 cm Q 0000638834 00000 n /Subtype /Form >> 0000171867 00000 n 0 0.087 TD 0.397 0.087 TD /Length 66 /F3 0.217 Tf -0.007 Tc /Length 67 q q >> 0.35 0.337 0.372 0.314 0.399 0.314 c stream q >> 0 0.464 m /Meta2212 Do 45.663 0 0 45.168 202.506 542.777 cm /Meta2201 Do /FormType 1 BT 0000124322 00000 n 0000627135 00000 n /Font << /Subtype /Form endstream Q Q endobj 0.267 0 l q 0.458 0 0 RG q Q q /Subtype /Form q 0000539682 00000 n Q 0 g -0.002 Tc 0000683052 00000 n >> [(31)] TJ /FormType 1 /Matrix [1 0 0 1 0 0] 0 0.087 TD /Subtype /Form stream /Matrix [1 0 0 1 0 0] /BBox [0 0 0.263 0.283] Q /Type /XObject 1794 0 obj << 45.214 0 0 45.413 81.303 614.294 cm q 1985 0 obj << 0 G /Subtype /Form ET l a� yt�( �T 6 7 9 m } j ^ ^ ^ $$If agd�( � kd�$$If T �l � �F ���,"�� �D �� q 45.663 0 0 45.147 426.844 373.394 cm q 1903 0 obj << 0.564 G 45.324 0 0 45.147 54.202 101.629 cm 0000302513 00000 n endobj q Q 0.35 0.087 TD q /Meta2316 Do /Matrix [1 0 0 1 0 0] 0 G /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /BBox [0 0 9.523 0.314] /Type /XObject endobj q BT Q Q Q 1 g 0 0.283 m 1.732 0.087 TD Q 0000188916 00000 n endstream 45.249 0 0 45.147 329.731 462.226 cm /Length 55 BT /Length 503 /F1 0.217 Tf /Meta1753 Do q /F1 6 0 R 0.397 0.087 TD /Meta2220 2246 0 R /Length 55 /Matrix [1 0 0 1 0 0] W* n 0000352838 00000 n 0.001 Tc 0 w endstream q 0.458 0 0 RG endobj 0 G /F3 23 0 R q Q 0 g 45.214 0 0 45.413 81.303 571.384 cm >> 1998 0 obj << /Meta2114 2136 0 R 45.233 0 0 45.168 105.393 268.001 cm W* n 0.458 0 0 RG 45.249 0 0 45.413 329.731 328.979 cm Q [(=)] TJ /Matrix [1 0 0 1 0 0] W* n 45.249 0 0 45.147 441.9 131.742 cm q 0000574236 00000 n 0000334577 00000 n q /Subtype /Form /Type /XObject /BBox [0 0 1.547 0.283] Q q 0 w /Font << 0000804598 00000 n 0 0.283 m 0000319774 00000 n 0 w Q 0 0 l 0 0 l 0.5 0.299 l >> Q 1 g 45.527 0 0 45.147 523.957 343.282 cm Q q 0 0 l 0 0 l BT q Q /Font << /Meta1895 1917 0 R 1 J 0.015 w 1 g q /BBox [0 0 9.523 0.314] 0.564 G 0000441079 00000 n /Font << 0.267 0.283 l q endobj /Subtype /Form 1975 0 obj << endstream Q Q 0 G BT BT Q stream /FormType 1 0000061005 00000 n 0.181 0.087 TD 0000312119 00000 n 0000545641 00000 n >> 0000160324 00000 n /Matrix [1 0 0 1 0 0] /BBox [0 0 0.413 0.283] /Font << S 0 0 l q 0 0 l 0000502041 00000 n Work Outside � In ( Write out EMBED Equation.DSMT4 first ( Now, plug all of g: ( ) in for x ( Simplify ( What if we were trying to find EMBED Equation.DSMT4 ? /Length 67 /Subtype /Form 0 g /BBox [0 0 1.547 0.464] /FormType 1 0 G 0000140330 00000 n 0000554023 00000 n 0.2 0.158 TD /Subtype /Form Q 0.185 0.165 l >> S 0000430975 00000 n /Meta1882 1904 0 R /Meta2326 Do 1.216 0.087 TD stream /Length 102 0 G >> Q /FormType 1 0 0.087 TD /Subtype /Form /FormType 1 0 0.283 m endobj >> 0 g 0000152933 00000 n /Subtype /Form /Type /XObject 0 G q /FormType 1 0000046265 00000 n 1.133 0.087 TD >> 0 0.087 TD 0000801136 00000 n 0 0 l q Q /BBox [0 0 9.523 0.464] 0000133062 00000 n /FormType 1 0.416 0.296 m 1.547 0.283 l ) which is correct Roots Name_____ Date_____ Class _____ 1 ) which correct. 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